PhysicsTeacher.in

High School Physics

Projectile Motion Formula class 11

Last updated on August 25th, 2023 at 09:43 am

This post on Projectile Motion Formula for class 11 presents a set of formulas that describe a projectile motion that is parabolic in nature and helps to find out important motion parameters as well. Let’s find out those formulas one by one, along with a brief idea for each formula.

Projectile Motion Formula for Class 11

The formula that describes the motion path or trajectory is as follows:
y = (tanθ) x – (1/2) g . x2/(V0 cosθ)2

Regarding Time we have 2 formulas listed below.

Time to reach max height: tmax= (V0sinθ )/g

Total time of flight for a projectile: Ttot = 2(V0sinθ )/g

Here is the formula to find out the maximum height reached by the projectile.

Maximum height reached: Hmax = ( V0sinθ )2/(2 g)

As a projectile traverses horizontal distance as well, here are the formulas for range (horizontal range).

Horizontal range of a projectile: R = (V0sin2θ )/g

Maximum possible horizontal range: Rmax = V0/ g

If we want to find out horizontal displacement at any interval of time, here is the formula to be used:

At time T=t,
Displacement along X-axis:
x= V0x.t = (V0 cosθ). t

If we want to find out vertical displacement at any interval of time, here is the formula to be used:

At time T=t,
Displacement along Y-axis:
y = (V0sinθ ).t  – (1/2) g t2

Also read: projectile motion numericals

See also  Terminal Velocity, Free Fall, & Drag force
Scroll to top
error: physicsTeacher.in