Last updated on August 25th, 2023 at 09:43 am
This post on Projectile Motion Formula for class 11 presents a set of formulas that describe a projectile motion that is parabolic in nature and helps to find out important motion parameters as well. Let’s find out those formulas one by one, along with a brief idea for each formula.
Projectile Motion Formula for Class 11
The formula that describes the motion path or trajectory is as follows:
y = (tanθ) x – (1/2) g . x2/(V0 cosθ)2
Regarding Time we have 2 formulas listed below.
Time to reach max height: tmax= (V0sinθ )/g
Total time of flight for a projectile: Ttot = 2(V0sinθ )/g
Here is the formula to find out the maximum height reached by the projectile.
Maximum height reached: Hmax = ( V0sinθ )2/(2 g)
As a projectile traverses horizontal distance as well, here are the formulas for range (horizontal range).
Horizontal range of a projectile: R = (V02 sin2θ )/g
Maximum possible horizontal range: Rmax = V02 / g
If we want to find out horizontal displacement at any interval of time, here is the formula to be used:
At time T=t,
Displacement along X-axis: x= V0x.t = (V0 cosθ). t
If we want to find out vertical displacement at any interval of time, here is the formula to be used:
At time T=t,
Displacement along Y-axis: y = (V0sinθ ).t – (1/2) g t2
Also read: projectile motion numericals