# Projectile Motion Formula class 11

Last updated on August 25th, 2023 at 09:43 am

This post on **Projectile Motion Formula for class 11 **presents a set of formulas that describe a projectile motion that is parabolic in nature and helps to find out important motion parameters as well. Let’s find out those formulas one by one, along with a brief idea for each formula.

**Projectile Motion Formula** for Class 11

The formula that describes the motion path or trajectory is as follows:

y = (tanθ) x – (1/2) g . x^{2}/(V_{0}cosθ)^{2}

Regarding **Time** we have 2 formulas listed below.

Time to reach max height:t_{max}= (V_{0}sinθ )/g

Total time of flight for a projectile:T=_{tot}2(V_{0}sinθ )/g

Here is the formula to find out the **maximum height** reached by the projectile.

Maximum height reached:H_{max}= ( V_{0}sinθ )^{2}/(2 g)

As a projectile traverses horizontal distance as well, here are the **formulas for range (horizontal range).**

Horizontal range of a projectile:R = (V_{0}^{2 }sin2θ )/g

Maximum possible horizontal range:R_{max}= V_{0}^{2 }/ g

If we want to find out **horizontal displacement at any interval of time**, here is the formula to be used:

At time T=t,

Displacement along X-axis:x= V_{0x}.t = (V_{0}cosθ). t

If we want to find out **vertical displacement at any interval of time**, here is the formula to be used:

At time T=t,

Displacement along Y-axis:y = (V_{0}sinθ ).t – (1/2) g t^{2}

Also read: projectile motion numericals