Maximum height of Projectile formula
In this post, we will focus on the formula to find the maximum height traversed by a projectile.
Maximum height of the Projectile formula
The equation to find the maximum height reached by a projectile is as follows:
Hmax = ( V0sinθ )2/(2 g)
Derivation of the Maximum height of the Projectile formula
To derive this formula we will refer to the figure below.
![how to calculate the Maximum Height reached by a projectile](https://physicsteacher.in/wp-content/uploads/2021/04/image-22.png)
Let’s say, the maximum height reached is Hmax.
When the projectile reaches the maximum height then the velocity component along Y-axis i.e. Vy becomes 0. And, V0sinθ is the initial velocity along the Y-axis.
Using one of the motion equations, we can write
(Vy)2 =( V0sinθ )2 – 2 g Hmax
=> 0 = ( V0sinθ )2 – 2 g Hmax
=> Hmax = ( V0sinθ )2/(2 g) This is the equation to find the maximum height reached by a projectile.