# Maximum height of Projectile formula

In this post, we will focus on the formula to find the maximum height traversed by a projectile.

**Maximum height of the Projectile formula**

The equation to find the maximum height reached by a projectile is as follows:

H_{max}= ( V_{0}sinθ )^{2}/(2 g)

**Derivation** of the **Maximum height of the Projectile formula**

To derive this formula we will refer to the figure below.

Let’s say, the **maximum height** reached is H_{max}.

When the projectile reaches the maximum height then the velocity component along Y-axis i.e. V_{y} becomes 0. And, V_{0}sinθ is the initial velocity along the Y-axis.

Using one of the motion equations, we can write

(V

_{y})^{2}=( V_{0}sinθ )^{2}– 2 g H_{max}

=> 0 = ( V_{0}sinθ )^{2}– 2 g H_{max}

=>

HThis is the equation to find the maximum height reached by a projectile._{max}= ( V_{0}sinθ )^{2}/(2 g)