PhysicsTeacher.in

High School Physics

Maximum height of Projectile formula

In this post, we will focus on the formula to find the maximum height traversed by a projectile.

Maximum height of the Projectile formula

 The equation to find the maximum height reached by a projectile is as follows:
Hmax = ( V0sinθ )2/(2 g)

Derivation of the Maximum height of the Projectile formula

To derive this formula we will refer to the figure below.

how to calculate the Maximum Height reached by a projectile
projectile motion: components of initial velocity V0

Let’s say, the maximum height reached is Hmax.
When the projectile reaches the maximum height then the velocity component along Y-axis i.e. Vy becomes 0. And, V0sinθ is the initial velocity along the Y-axis.

Using one of the motion equations, we can write

(Vy)2 =( V0sinθ )2 – 2 g Hmax
=> 0 = ( V0sinθ )2 – 2 g Hmax

=> Hmax = ( V0sinθ )2/(2 g) This is the equation to find the maximum height reached by a projectile.

See also  Velocity time graph - Comprehensive Guide
Scroll to top
error: physicsTeacher.in