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You throw an object straight up such that it leaves your hand with a speed of 9.7 m s−1. how long after you let it go does the ball reach its maximum height?

Question: You throw an object straight up such that it leaves your hand with a speed of 9.7 m s−1. how long after you let it go does the ball reach its maximum height?

Solution:

Initial velocity u= 9.7 m/s
Say, Time required to reach the maximum height = t

As per the vertical motion formula: t= u/g = 9.7/9.8 s = 0.99 s.

After it leaves the thrower’s hand, the ball takes 0.99 s to reach its maximum height. {Answer]

See also  Approximately how fast must you toss a ball straight up in order for it to take 2 seconds to return to the level from which you tossed it?
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