Question: You throw an object straight up such that it leaves your hand with a speed of 9.7 m s−1. how long after you let it go does the ball reach its maximum height?

**Solution:**

Initial velocity u= 9.7 m/s

Say, Time required to reach the maximum height = t

As per the vertical motion formula: t= u/g = 9.7/9.8 s = 0.99 s.

After it leaves the thrower’s hand,

the ball takes 0.99 sto reach its maximum height. {Answer]