Maximum height of Projectile formula
In this post, we will focus on the formula to find the maximum height traversed by a projectile.
Maximum height of the Projectile formula
The equation to find the maximum height reached by a projectile is as follows:
Hmax = ( V0sinθ )2/(2 g)
Derivation of the Maximum height of the Projectile formula
To derive this formula we will refer to the figure below.
Let’s say, the maximum height reached is Hmax.
When the projectile reaches the maximum height then the velocity component along Y-axis i.e. Vy becomes 0. And, V0sinθ is the initial velocity along the Y-axis.
Using one of the motion equations, we can write
(Vy)2 =( V0sinθ )2 – 2 g Hmax
=> 0 = ( V0sinθ )2 – 2 g Hmax
=> Hmax = ( V0sinθ )2/(2 g) This is the equation to find the maximum height reached by a projectile.