# Force and Pressure Class 8 Numerical

Last updated on June 25th, 2023 at 04:41 pm

In this post, we will solve **Numerical problems based on the Force and Pressure chapter of class 8 science**. Here, first, we will go through the *formula of pressure* & other related data, and then attempt the numerical questions. Solution & answer is given for all the numerical questions.

**Related Post**: **Light class 8 numerical solved**

**Formulas Used**

Formula of pressure is as follows:

Pressure = Force / [Area on which the force in applied]

The air pressure at the sea level is called 1 atmosphere pressure. Air pressure decreases as one goes up in height from the sea level.

1 Atmosphere = 101 kPa = 101 x 10^{3 }Pa = 1 bar = 10^{3}mbar

**Force and Pressure Class 8 Numerical Questions and Answers** [solved]

Example 1.The area of the bottom of a tiffin box is 0.25 m^{2}and weight is 50 N, Calculate the pressure exerted by the box on the shelf.

**Solution:**

Given: Area = 0.25 m

^{2}, weight of the box = 50 N, Pressure = ?Pressure =force/area = 50 N/0.25 m

^{2}= 200 N/ m^{2}

Example 2.The area of the tip of a screw is 0.5 mm^{2 }and its weight is 0.5 N. Calculate the pressure (in Pa) exerted by the screw on a wooden plank.

**Solution:**

Given: Area = 0.5 x10

^{-6}m^{2}Weight of the screw = 0.5 N, Pressure =?

Pressure =weight/area =0.5N

/(0.5×10^{-6 }m^{2}) = 10^{6 }N/m^{2}= 10^{6 }Pa

Example 3.Mass of a block of metal is 10 kg and its dimensions are length 50 cm, breadth 10 cm, height 20 cm. (See fig.) If the metal block is placed on the following surface on the table, find out on which of the surface ABCD, CDEF and BCFG will the pressure exerted on the table be maximum.

**Solution:**

**Given: **Weight of the block = mg =10 x 9.8N =98 N

For the surface ABCD, length = 50 cm, height = 20 cm.

Area = 50 cm x 20 cm= 1000 cm

^{2}= 0.1 m^{2}

Pressure = weight/area= 98/(0.1) = 980 Pa

For the surface CDEF, length = 50 cm, breadth = 10 cm

Area = 50 cm x 10 cm = 500 cm

^{2}= 0.05 m^{2}

Pressure =weight/area= 98/0.05 = 9800/5 = 1960 Pa

For the surface BCFG, height = 20 cm, breadth = 10 cm

Area = 20 cm x 10 cm = 200 cm

^{2}= 0.02 m^{2}

Pressure =weight/area= 98 N/0.02 m^{2}= 4900 Pa

**From all 3 cases, we found that the Maximum Pressure is on the surface BCFG.**

* Hence, the *smaller the area of contact, the larger

**the pressure.**