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Pressure Numericals class 9

Last updated on June 25th, 2023 at 01:53 pm

In this post, you will find a set of Pressure Numericals for class 9, where we have solved selected practice problems based on the Pressure formula (in terms of thrust or perpendicular force). As a reference, we have added the definition, formula, and SI unit of pressure.

Formula Used

Pressure can be calculated from this formula or Pressure equation
Pressure = perpendicular Force /Area = thrust / area
P = F/A

Pressure Numericals for class 9 [with solutions]

1 ] A water glass sitting on a table weighs 4 N. The bottom of the water glass has a surface area of 0.003 m^2. Calculate the pressure the water glass exerts on the table.

solution:
Force or thrust here =F= 4 N
Area A = 0.003 m^2
Pressure exerted = P = F/A = 4/0.003 Pa = 1333.33 Pa

2] A student weighs 600 N. The student’s shoes are in contact with the floor over a surface area of 0.012 m^2. Calculate the pressure exerted by the student on the floor.

solution:
Force or thrust here =F=600 N
Area A = 0.012 m^2
Pressure exerted = P = F/A = 600/0.012 Pa = 5 x 10^4 Pa

3] A box that weighs 250 N is at rest on the floor. If the pressure exerted by the box on the floor is 25,000 Pa, over what area is the box in contact with the floor?

solution:
Force or thrust here =F=250 N
Pressure exerted = P = 25,000 Pa
So the Area in contact A =F/P= 250/25000 m^2 = 0.01 m^2

4] If You are holding a 2-kg book in the palm of your hand and if the area of contact between your hand and the book is 0.003 m^2 then find out the pressure that is exerted on your hand by the book.

See also  pulley systems: block and tackle

Solution:
Force = F = 2 x 9.8 N = 19.6 N
Area = 0.003 m^2
Pressure = F/A = 19.6/0.003 Pa =6533.33 Pa

Pressure definition

The pressure is the force per unit area that is applied on the surface of an object. Pressure increases if the force applied increases, and decreases if the area of contact increases.

Pressure Unit in SI

The unit of pressure in the SI system is the Pascal, abbreviated Pa. One pascal is equal to a force of 1 N applied over an area of 1 m^2, or 1 Pa = 1 N/m^2.

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