Calorimetry Numericals class 10

Last updated on June 25th, 2023 at 02:27 pm

In this post and its supporting posts, we will solve a set of Calorimetry Numericals for class 10. The problems are taken from Selina’s ICSE Class 10 Physics book. The solution link after each problem will lead you to the solution to the problem in a new tab of your browser.

Calorimetry Numericals for class 10 ICSE [Selina class 10 physics solution]

Question: 1

By imparting heat to a body, its temperature rises by 15⁰C. What is the corresponding rise in temperature on the Kelvin scale?

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Question: 2

(a)Calculate the heat capacity of a copper vessel of mass 150 g if the specific heat capacity of copper is 410 J kg-1 K-1.

(b)How much heat energy will be required to increase the temperature of the vessel in part (a) from 25^oC to 35^oC?

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Question: 3

A piece of iron of mass 2.0 kg has a heat capacity of 966 J K-1. Find
(i) Heat energy needed to warm it by 15^oC, and
(ii) Its specific heat capacity in S.I unit.

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Question: 4

Calculate the amount of heat energy required to raise the temperature of 100 g of copper from 20^oC to 70^oC. Specific heat of capacity of copper =390 J kg-1 K-1.

Solution

Question: 5

1300 J of heat energy is supplied to raise the temperature of 0.5 kg of lead from 20^oC to 40^oC. Calculate the specific heat capacity of lead.

Solution

Question: 6

Find the time taken by a 500 W  heater to raise the temperature of 50 kg of material of specific heat capacity 960 J kg-1 K-1, from 18^oC to 38^oC. Assume that all the heat energy supplied by heater is given to the material.

Solution

Question: 7

An electric heater of power 600 W raises the temperature of 4.0 kg of a liquid from 10.0⁰C to 15.0⁰C in 100 s. Calculate:
(i) the heat capacity of 4.0 kg of liquid, and
(ii) the specific heat capacity of liquid

Solution

Question: 8

0.5 kg of lemon squash at 30^o C is placed in a refrigerator which can remove heat at an average rate of 30 J s-1. How long will it take to cool the lemon squash to 5^o C? Specific heat capacity of squash = 4200 J kg-1 K-1.

Solution

Question: 9

A mass of 50 g of a certain metal at 150° C is immersed in 100 g of water at 11° C. The final temperature is 20° C. Calculate the specific heat capacity of the metal. Assume that the specific heat capacity of water is 4.2 J g-1 K-1.

Solution

Question: 10

45 g of water at 50^o C in a beaker is cooled when 50 g of copper at 18^oC is added to it. The contents are stirred till a final constant temperature is reached. Calculate the final temperature. The specific heat capacity of copper is 0.39 J g-1 K-1 and that of water is 4.2 J g-1 K-1. State the assumptions used.

Solution

Question: 11

200 g of hot water at 80^o C is added to 300 g of cold water at 10^oC. Neglecting the heat taken by the container, calculate the final temperature of the mixture of water. Specific heat capacity of water = 4200 J kg-1 K-1.

Solution

Question: 12

The temperature of 600 g of cold water rises by 15^o C when 300 g of hot water at 50^o C is added to it. What was the initial temperature of the cold water?

Solution

Question: 13

1.0 kg of water is contained in a 1.25 kW kettle. Calculate the time taken for the temperature of water to rise from 25° C to its boiling point 100° C. Specific heat capacity of water = 4.2 J g-1 K-1.

Solution