Last updated on December 5th, 2022 at 09:11 am

Here we will solve a bunch of **Gravitation Numericals** from the Gravitation chapter of high school Physics, covering gravitational force and gravitational constant. This is a well-crafted set of **Solved Numericals on Gravitation for class 9** (Gravitation *Numericals worksheet for class 9) *that you should try. The solution to this **Gravitation class 9 Numericals worksheet **is also provided at the end of this worksheet.

This solved question-answer set is appropriate for high school students of IGCSE, ICSE, CBSE, and State Boards, and is good for competitive exams as well.

**Gravitation Numericals for class 9 | Solved Numericals on Gravitation for class 9**

**1 ] Find the gravitational force of attraction between a body of unit mass and the Moon.**

Mass of the moon = 7.4 x 10^22 kg

radius of the moon = 1.74 x 10^6 m

G = 6.67 x 10^(-11) N-m^2/kg^2

**2 ] What is the gravitational force between the Sun and the Earth? **

(take, the mass of the Sun = 1.99 x 10^30 Kg.

mass of the Earth = 6 x 10^24 Kg

G = 6.67 x 10^(-11) N-m^2/kg^2

and distance between the Sun and the Earth=1.49 x 10^11 m)

**3 ] Find the acceleration due to gravity on the surface of Jupiter using the data given below;**

(Mass of Jupiter: M = 1.9 x 10^27 kg,

the radius of Jupiter = R = 7 x 10^7 m

**4 ] A body weighs 25 kg on the surface of the earth. if the mass of the earth is 6 x 10^24 kg, the radius of the earth is 6.4 x 10^6 m, and the gravitational constant =6.67 x 10^(-11) N-m^2/kg^2. ****Calculate (a) the acceleration produced in the body ****(b) the acceleration produced in the earth.**

**5 ] Estimate the gravitational force between 2 protons separated by a distance of 1 angstrom.**

**mass of proton = 1.6 x 10^(-27) kg**

**6 ] Two bodies A and B of masses m and 2m respectively are kept at a distance d apart. Where should a small particle be placed, so that the net gravitational force on it due to the bodies A and B is zero?**

**7 ] Consider a heavenly body whose mass is half that of the earth and its radius is also half that of the earth. What is the acceleration due to gravity at the surface of this heavenly body? (Take acceleration due to gravity at the surface of the earth = 10 m/s^2)**

**Solved Numericals on Gravitation for class 9** |** Gravitation class 9 Numericals worksheet**

**Solution**

**1] Solution to Q1**

**2] Solution to – Q2**

**3 ] Solution of Q3**

**4 ] Solution of Q4**

**5 ] Solution of Q5**

**6 ] Solution of Q6**

The particle must be placed between A and B bodies, on the line AB, to cancel out the gravitational forces on the particle. Suppose it’s at a distance x from A. So it will be at a distance (d-x) from B. Let its mass is m* ^{I}* .

**7 ] Solution of Q7**

**g= GM / R ^{2} = [G (M_{e}/2)]/(R_{e}/2)^{2} = 2 (G M_{e}/R_{e}^{2} ) = 2 g_{ earth} = 2 x 10 m/s^{2} = 20 m/s^{2}**

The summary of this post:

**Reference & Related Study**

**Reference**: **Newton’s Law of Gravitation**

Related Study: **Gravitation Class 11 Notes**