**Question: 2**

**(a)Calculate the heat capacity of a copper vessel of mass 150 g if the specific heat capacity of copper is 410 J kg****-1 ****K****-1****.**

**(b)How much heat energy will be required to increase the temperature of the vessel in part (a) from 25 ^{o}C to 35^{o}C?**

**Solution:**

(a) Given

Mass of copper vessel = 150 g = 0.15 kg

The specific heat capacity of copper = 410 J kg-1 K-1

We know that,

Heat capacity = Mass × specific heat capacity = 0.15 kg × 410 J kg-1 K-1 = 61.5 JK-1

[b] Change in temperature =△T= (35 – 25)^{0} C = 10^{0} C = 10 K

The energy required to increase the temperature of vessel △Q = mc△T

△Q = 0.15 × 410 × 10

△Q = 615 J