# Motion in 2 and 3 Dimensions – formula & numerical

We will discuss and list down the formulae of position, velocity, and acceleration related to the Motion in two and three Dimensions using unit vectors i, j, and k format.

We will list down the 2-Dimensional equivalent of motion equations or suvat equations. Also, we will solve numerical problems using the formulas of the position vector, velocity vector, and acceleration vector in 2 Dimension and 3 Dimension.

## Position formula (in 3 dimensions)

In three dimensions, the location of a particle is specified by its location vector, r:
r = x i + y j + z k

If during a time interval ∆t the position vector of the particle changes from r1 to r2, the displacement ∆r for that time interval is represented as: ∆r = r1 − r2
= (x2 − x1)i + (y2 − y1)j + (z2 − z1)k
r= (∆x) i + (∆y) j + (∆z) k

## Velocity formulae (in 3 dimensions)

### Average velocity formula in 3 dimensions

If a particle moves through a displacement ∆r in a time interval ∆t then its average velocity for that interval is:
v =∆r/∆t =(∆x/∆t) i + (∆y/∆t) j + (∆z/∆t) k

### Instantaneous velocity formula in 3 dimensions

A more interesting quantity is the instantaneous velocity v, which is the limit of the average velocity when we shrink the time interval ∆t to zero.

Instantaneous velocity is the time derivative of the position vector r:
v =dr/dt = d(xi + yj + zk)/dt= (dx/dt) i +(dy/dt) j +(dz/dt) k
This Instantaneous velocity can be written as:
v = vxi + vyj + vzk
where vx = (dx/dt) vy =(dy/dt) vz =(dz/dt)

## Acceleration formulae (in 3 dimensions)

### Average acceleration formula in 3 dimensions

If a particle’s velocity changes by ∆v in a time period ∆t, the average acceleration a for that period is
a =∆v/∆t = ∆(vxi +vyj + vzk)/∆t = (∆vx/∆t)i +(∆vy/∆t) j + (∆vz/∆t)k

### Instantaneous acceleration formula in 3 dimensions

But a much more interesting quantity is the result of shrinking the period ∆t to zero, which gives us the instantaneous acceleration, a. It is the time derivative of the velocity vector v:
a =dv/dt=d(vxi +vyj + vzk)/dt = (dvx/dt)i +(dvy/dt)j + (dvz/dt)k
which can be written: a = axi + ayj + azk

where
ax =dvx/dt=d2x/dt2
ay =dvy/dt=d2y/dt2
az =dvz/dt =d2z/dt2

## 2 dimensional Motion equations in vector format with Constant Acceleration

2-D motion equations – Let’s talk about the Motion equations in 2 dimensions when we have Constant Acceleration in Two Dimensions.

When the acceleration a (for motion in two dimensions) is constant we have two sets of equations to describe the x and y coordinates, each of which is similar to the suvat equations.

In the following discussion, the motion of the particle begins at t = 0.

The initial position of the particle is given by r0 = x0i + y0j
and its initial velocity is given by v0 = v0xi + v0yj
and the acceleration vector a = axi + ayj is constant.

## Worked Examples | Solved Numerical problems

Let’s solve a few selected numerical problems on Motion in 2 and 3 Dimensions using the formulae of the position vector, velocity vector, and acceleration vector in 2 Dimensions.

1. The position of an electron is given by r = 3.0t i − 4.0t^2 j + 2.0 k (where t is in seconds and the coefficients have the proper units for r to be in meters).
(a)What is v(t) for the electron? (b) In unit–vector notation, what is v at t = 2.0 s?
(c) What are the magnitude and direction of v just then?

Solution:
1. A particle moves so that its position as a function of time in SI units is r = i + 4t^2 j + t k. Write expressions for (a) its velocity and (b) its acceleration as functions of time.

Solution:

Motion in 2 and 3 Dimensions – formula & numerical
Scroll to top
error: physicsTeacher.in