# Temparature conversion Numericals class 8

In this post, we will solve a few selected Numericals based on temperature conversion formulas. Now, let’s find the required formulas first.

**Formula used**

Temperature is measured in units of Celsius (^{0}C), Fahrenheit (^{0F),} and Kelvin (K). Kelvin is used in scientific experiments, while the other two are used in daily life. The relation between the three units is shown by the following formulae.

C/5 = (F-32)/9 ………….. (1)

K = C + 273.15 …………………. (2)

**Temparature Conversion Numericals class 8** [solved]

**1 ] How much will the temperature of 68 ^{0}F be in Celsius and Kelvin?**

Solution:

Given : Temperature in Fahrenheit = F = 68, Temperature in Celsius = C= ?,

The temperature in Kelvin = K =?

According to the formula: C/5 = (F-32)/9

=> C/5 = (68-32)/9 = 4

=>C = 4×5 = 20 ^{0}C

K = C + 273.15 = 20 + 273.15 = 293.15

Thus, the temperature in Celsius = 20 ^{0}C and in Kelvin = 293.15 K

**2 ] At what temperature will its value be the same in Celsius and in Fahrenheit?**

Given: If the temperature in Celsius is C, then the temperature in Fahrenheit (F) will be the same,

i.e. F= C.

C/5 = (F-32)/9

=> C/5 = (C-32)/9

=>(C-32)x 5 = Cx9

=>5C – 160 = 9 C

=>C = -40

So, F = C = -40

The temperatures in Celsius and in Fahrenheit will be the same at – 40^{0}