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Temparature conversion Numericals class 8

In this post, we will solve a few selected Numericals based on temperature conversion formulas. Now, let’s find the required formulas first.

Formula used

Temperature is measured in units of Celsius (0C), Fahrenheit (0F), and Kelvin (K). Kelvin is used in scientific experiments, while the other two are used in daily life. The relation between the three units is shown by the following formulae.

C/5 = (F-32)/9 ………….. (1)
K = C + 273.15 …………………. (2)

Temparature Conversion Numericals class 8 [solved]

1 ] How much will the temperature of 68 0F be in Celsius and Kelvin?

Solution:

Given : Temperature in Fahrenheit = F = 68, Temperature in Celsius = C= ?,
The temperature in Kelvin = K =?
According to the formula: C/5 = (F-32)/9

=> C/5 = (68-32)/9 = 4
=>C = 4×5 = 20 0C

K = C + 273.15 = 20 + 273.15 = 293.15

Thus, the temperature in Celsius = 20 0C and in Kelvin = 293.15 K

2 ] At what temperature will its value be the same in Celsius and in Fahrenheit?

Given: If the temperature in Celsius is C, then the temperature in Fahrenheit (F) will be the same,
i.e. F= C.

C/5 = (F-32)/9
=> C/5 = (C-32)/9
=>(C-32)x 5 = Cx9
=>5C – 160 = 9 C
=>C = -40

So, F = C = -40
The temperatures in Celsius and in Fahrenheit will be the same at – 400

See also  Numericals on Young modulus
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