Numerical question: Approximately how fast must you toss a ball straight up in order for it to take 2 seconds to return to the level from which you tossed it?

**Solution:**

Here we have to find out the initial velocity u.

Total time of upward and downward motion = 2 s

That means the time required to reach the maximum height = 1 s.

Say, initial velocity = u

Using the formula: T

_{upward}= u/g

T_{upward}= 1

=> u/g = 1

=> u = g

=> u= 9.8Initial velocity with which the ball is to be tossed initially = 9.8 m/s [Answer]