Ohm’s Law | Ohm’s law statement

What is Ohm’s Law?

Ohm’s law states that the current through a metallic element is proportional to the potential difference applied between its ends, provided the temperature remains constant.

How to derive Ohm’s Law formula?

If a current I passes through a metallic element when a potential difference V is applied to that element (between its 2 ends), then we can write
I ∝ V
Here comes a proportionality constant (1/R) and the Ohm’s law equation becomes,
I = (1/R) V
=> I = V/R
or, V = IR ………………. (1)
Here, Here R is a constant for the given element and is called its resistance.
Thus, this law of Ohm can be expressed with the equation or formula, V = IR
Thus, the derivation of Ohm’s law is done.

So we have seen that this law of Ohm can be expressed with the formula or equation, V = IR
where V is the potential difference across the metallic element and I is the current flowing through the element. R is the electrical resistance of the element.

Draw the VI graph for Ohmic conductors

Ohm's law
VI Graph for Ohmic conductors

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How can we verify Ohm’s Law using an Experiment?

What we need for the Ohm’s law Experiment or verification test

What we need:
Four or five dry cells,
a thin wire (AB),
a voltmeter,
an ammeter,
a plug key
and some thick connecting wires.

Steps to execute Ohm’s law experiment

1> We have to start the test with a single cell. We have to connect the circuit as shown in Figure a.
– The ammeter will show us the current I flowing through the circuit, and the voltmeter will measure the potential difference V between the ends A and B of the wire.
– We have to note these values. (1st set of test data) Remember that this set of measured V and I are for a single cell setup.

ohm's law
Single cell



2> Now we have to connect two cells in series in the circuit, as shown in Figure b.
– We will find that the reading of the voltmeter increases. This means that a larger potential difference has been applied across the wire AB.
– This is obvious as we have in this case applied 2 cells in series.
– We will also find that the reading of the ammeter has increased as well. We have to note down the new values of V and I. (2nd Set of test data)

ohm's law
2 cells in series

3> We have to repeat the experiment by connecting in series three cells, four cells, and so on. In each case measure the potential difference and the current. (3rd Set, 4th Set….of test data)

4> If we calculate V/I for each test data set, we will find that it is almost the same.
– So, V/I = R is a constant, which is another way of stating the law of Ohm. Here, R is the resistance of the wire AB.

Ohm’s law graph: If we plot a graph of the current I against the potential difference V, it will be a straight line (Figure c). This shows that the current is proportional to the potential difference.

Ohm's law
(c) V-I Graph

How to use Ohm’s law formula to solve numerical problems

Q: A 10 V battery is connected to a lamp of resistance 4 Ohm. calculate the current through the lamp.

A: From the law of Ohm, current i = V/R =( 10 / 4 ) A = 2.5 A.

A means Ampere, unit of current.

Conclusion

I hope you have liked this post on the law of Ohm. It’s a very interesting and important law of electricity chapter in Physics courses. This law also gives rise to the concept of Resistance. We will publish posts on resistance and Numericals on Law of Ohm very soon for high school students.

Ohm’s Law | Ohm’s law statement
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