 # Solution of Physics Numericals for class 9 (set 1 Q16)

Last updated on November 6th, 2020 at 09:29 am

## Problem Statement

A bullet of mass 50 g moving with an initial velocity of 100 m/s, strikes a wooden block and comes to rest after penetrating a distance 2 cm in it.

Calculate:
(i) Initial momentum of the bullet

(ii)final momentum of the bullet
(iii) retardation caused by the wooden block, and
(iv) resistive force exerted by the wooden block

Solution:

Mass = m=50 g = 50/1000 kg =0.05 kg

Initial velocity =u = 100 m/s

Final velocity = v= 0

Distance travelled before stopping =s= 2 cm = 0.02 m

Initial momentum = mu=0.05 X 100 kg m/s=5 kgm/s

Final momentum = mv = 0  [as v=0]

Let retardation be a.

We will use the equation, v^2=u^2-2as     [ – sign for retardation. The bullet finally stops, that means it had a retardation]

as v=0, the equation becomes
0 = u^2 -2 a s
=> a = u^2/(2s) = (100 X 100)/(2X0.02) = 250000 m/s^2

So Retardation is 250000 m/s^2

Resistive force applied by the block = ma = 0.05 x 250000 N= 12500 N

See also  Vertical motion when a ball is thrown vertically upward with derivation of equations
Scroll to top
error: physicsTeacher.in