Solution of Physics Numericals for class 9 (set 1 Q13)
Last updated on November 6th, 2020 at 09:13 am
Problem Statement
A cricket ball of mass 100 g moving at a speed of 30 m/s is brought to rest by a player in 0.03 s. find the average force applied by the player.
Solution:
mass =m= 100 g = 100/1000 kg = 0.1 kg
initial velocity = u=30 m/s
Final velocity = v=0
Time duration = t = 0.03 s
Acceleration = (v-u)/t = (0-30)/0.03 = – 3000/3 = -1000 m/s^2
Average Force = mass * acceleration = 0.1 * (-1000) N = -100N
The magnitude of force is 100 N and the negative sign signifies that it is applied in the direction opposite to the direction of motion of the ball.
