Go to ...

PhysicsTeacher.in

High School Physics BLOG - online class notes

RSS Feed

October 19, 2019

Solution of Physics Numericals for class 9 (set 1 Q12)


Problem Statement

A force acts for 0.1 sec on a body of mass 2 kg initially at rest. The force is then withdrawn and the body moves with a velocity of 2 m/s. Find the magnitude of the force.

Solution of class 9 Set1 Q12

Solution:
 A force acts on a body for 0.1 sec. That means that body had acceleration for 0.1 sec.

So time duration = t = 0.1 sec

Initial velocity =u= 0

When the force is withdrawn, the velocity becomes 2 m/s.
That means, at the end of accelerated motion the final velocity = v=2 m/s

(Now, to find out the magnitude of force, we need to find out the value of acceleration. mass is already given)

  Acceleration a = (v-u)/t = (2-0)/0.1= 20 m/s^2

  And the magnitude of force (F) = ma= mass.Acceleration = 2 X 20 N = 40 N

  Answer: Magnitude of Force = 40 Newton

Next Problem

Previous Problem

error: Content is protected !!