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Solution of Physics Numericals for class 9 (set 1 Q12)

Last updated on November 6th, 2020 at 06:40 am

Problem Statement

A force acts for 0.1 sec on a body of mass 2 kg initially at rest. The force is then withdrawn and the body moves with a velocity of 2 m/s. Find the magnitude of the force.

Solution of class 9 Set1 Q12

 A force acts on a body for 0.1 sec. That means that body had acceleration for 0.1 sec.

So time duration = t = 0.1 sec

Initial velocity =u= 0

When the force is withdrawn, the velocity becomes 2 m/s.
That means, at the end of accelerated motion the final velocity = v=2 m/s

(Now, to find out the magnitude of force, we need to find out the value of acceleration. mass is already given)

  Acceleration a = (v-u)/t = (2-0)/0.1= 20 m/s^2

  And the magnitude of force (F) = ma= mass.Acceleration = 2 X 20 N = 40 N

  Answer: Magnitude of Force = 40 Newton

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