52) The area of base of a cylindrical vessel is 300 cm^2. Water (density = 1000 kg /m^3) is poured into it up to a depth of 6 cm. Calculate: (a) the pressure and (b) the thrust of water on the base. (g = 10 m/ s^2).
Pressure = hdg=(6/100)x1000x10 = 600 Pa…………….(answer of a)
Area = 300 cm^2 = 300/10000 m^2 = 0.03 m^2
Thrust = pressure x area = 600 x 0.03 N = 18 N…………(answer of b)
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Problems Set – grade 9