High School Physics

# Electricity Numericals class 10 worksheet

Last updated on June 22nd, 2023 at 12:08 pm

In this post, you will find a Worksheet based on the Electricity Numericals for class 10 of different boards like CBSE, ICSE, and other state boards. The problems are solved as well.

Electricity Numericals class 10 worksheet

1] The potential difference between the terminals of an electric iron is 240 V and the current is 5.0 A. What is the resistance of the electric iron?

Solution:
V = 240 volt, I = 5 A
We know that
V=IR
240 = 5 x R
R = 240/5 = 48 ohm.

2] An electric room heater draws a current of 2.4 A from the 120 V supply line. What current will this room heater draw when connected to the 240 V supply line?

Solution :
In the first case,
I = 2.4 amp, V = 120 volt
V=IR
120 = 2.4 x R
R = 120/2.4 = 50 ohm
So, the resistance of the heater is 50 ohm.
In the second case,
V = 240 volt, R = 50 ohm
V = IR
240 = I x 50
I =4.8 amp.

3] A p.d. of 10 V is needed to make a current of 0.02 A flow through a wire. What p.d. is needed to make a current of 250 mA flow through the same wire?

Solution :
In the first case,
I = 0.02 A, V = 10 volt

V=IR
10 = 0.02 x R
R = 10/0.02 = 500 ohm
This means the resistance of the wire is 500 ohm.

In the second case,
I = 250 x 10-3 A, R = 500 ohm

V = IR
V = 250 x 10-3 x 500
V = 125 volts.

4] A current of 200 mA flows through a 4 kΩ resistor. What is the p.d. across the resistor?

5] If the emf of a battery is 9 V, how much energy is converted from chemical to electrical when 2 C of charge flows?

Solution:
Here, Potential difference = emf of the battery = V= 9 V
Charge moved Q=2 C
Energy = work done= W
W = VQ
=> W = 9×2 J = 18 J

6] What is the p.d. across a resistor if 24 J of heat is produced when a current of 2 A flows through it for 10 s?

Solution:
Given:
Work done = energy =W= 24 J
Current I = 2 A
time t = 10 s

Total charge Q = I x t = 2×10 C = 20 C
We know, W = VQ
=>V = W/Q = 24/20 V= 1.2 V
Answer: p.d. across a resistoris 1.2 V

7] How much is work done in moving a charge of 4 C across two points having a potential difference of 24 V?

Solution:
Q = 4 C
potential difference PD = 24 V
Work done = W
W = PD x Q = 24 x 4 J = 96 J

8] What is the work done in moving a charge of 2 C from a point at 220 V to a point at 120 V?

Solution:
Q = 2 C
potential difference PD = (220-120)V = 100 V
Work done W = PD x Q = 100 x 2 J = 200 J

9] How much energy is given to each coulomb of charge passing through a 6 V battery? [NCERT]

Solution:
Given: Q = 1 C, PD = 6 V
Energy = Work done = W
W = PD x Q = 6 x 1 J = 6 J
So, Energy is given to each coulomb of charge passing through a 6 V battery is 6 J

10] 500 joules of work is done in transferring 40 coulombs of charge from one terminal of a battery to the other. What is the battery voltage?

Solution:
Work done W = 500 J, charge Q = 40 C,
Battery Voltage = V=?
We know, W = VQ
=> V = W/Q = 500/40 = 12.5 V

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