# Electricity Numericals class 10 worksheet

Last updated on June 22nd, 2023 at 12:08 pm

In this post, you will find a Worksheet based on the **Electricity Numericals for class 10** of different boards like CBSE, ICSE, and other state boards. The problems are solved as well.

**Electricity Numericals class 10 worksheet**

1] The potential difference between the terminals of an electric iron is 240 V and the current is 5.0 A. What is the resistance of the electric iron?

Solution:

V = 240 volt, I = 5 A

We know that

V=IR

240 = 5 x R

R = 240/5 = 48 ohm.

2] An electric room heater draws a current of 2.4 A from the 120 V supply line. What current will this room heater draw when connected to the 240 V supply line?

**Solution :**

In the first case,

I = 2.4 amp, V = 120 volt

V=IR

120 = 2.4 x R

R = 120/2.4 = 50 ohm

So, the resistance of the heater is 50 ohm.

In the second case,

V = 240 volt, R = 50 ohm

V = IR

240 = I x 50

I =4.8 amp.

3] A p.d. of 10 V is needed to make a current of 0.02 A flow through a wire. What p.d. is needed to make a current of 250 mA flow through the same wire?

**Solution :**

In the first case,

I = 0.02 A, V = 10 volt

V=IR

10 = 0.02 x R

R = 10/0.02 = 500 ohm

This means the resistance of the wire is 500 ohm.

In the second case,

I = 250 x 10^{-3} A, R = 500 ohm

V = IR

V = 250 x 10-3 x 500

V = 125 volts.

4] A current of 200 mA flows through a 4 kΩ resistor. What is the p.d. across the resistor?

**Solution :**

I = 200 mA = 0.2 A

R = 4 x 10^{3}ohm = 4000 ohm

We know that

V=IR

V = 0.2 x 4000

V = 800 volt.

5] If the emf of a battery is 9 V, how much energy is converted from chemical to electrical when 2 C of charge flows?

**Solution**:

Here, Potential difference = emf of the battery = V= 9 V

Charge moved Q=2 C

Energy = work done= W

W = VQ

=> W = 9×2 J = 18 J

Answer: 18 Joule

6] What is the p.d. across a resistor if 24 J of heat is produced when a current of 2 A flows through it for 10 s?

**Solution**:

Given:

Work done = energy =W= 24 J

Current I = 2 A

time t = 10 s

Total charge Q = I x t = 2×10 C = 20 C

We know, W = VQ

=>V = W/Q = 24/20 V= 1.2 V

Answer: p.d. across a resistoris 1.2 V

7] How much is work done in moving a charge of 4 C across two points having a potential difference of 24 V?

Solution:

Q = 4 C

potential difference PD = 24 V

Work done = W

W = PD x Q = 24 x 4 J = 96 J

8] What is the work done in moving a charge of 2 C from a point at 220 V to a point at 120 V?

**Solution:**Q = 2 C

potential difference PD = (220-120)V = 100 V

Work done W = PD x Q = 100 x 2 J = 200 J

9] How much energy is given to each coulomb of charge passing through a 6 V battery? [NCERT]

Solution:

Given: Q = 1 C, PD = 6 V

Energy = Work done = W

W = PD x Q = 6 x 1 J = 6 J

So, Energy is given to each coulomb of charge passing through a 6 V battery is 6 J

10] 500 joules of work is done in transferring 40 coulombs of charge from one terminal of a battery to the other. What is the battery voltage?

Solution:

Work done W = 500 J, charge Q = 40 C,

Battery Voltage = V=?

We know, W = VQ

=> V = W/Q = 500/40 = 12.5 V