Numerical problem – a ball thrown vertically upwards

Here, we will Solve the following numerical problem based on the vertical motion of a ball – when a ball is thrown vertically upwards.

Question

When a ball is thrown vertically upwards, it goes through a distance of 19.6 m. Find the initial velocity of the ball and the time taken by it to rise to the highest point. (Acceleration due to gravity, g=9.8 ms-2) [3 MARKS]

Solution:

Distance traversed =s=19.6 m

say, initial velocity = u

and, say the time taken to rise to the highest point = t

We know that the velocity at the highest v = 0

Using the following equation of motion with retardation, we can find the initial velocity = u

v2=u2– 2gs

=> 0 = u2 – 2 x 9.8 x 19.6

=> u2=19.6 x 19.6

u = 19.6 m upwards

To find out the the time taken to rise to the highest point (t) we will use the following equation:

v = u – gt

=> 0 = u – gt

=> t = u/g = 19.6/9.8 s = 2 seconds

Know more about the vertical motion formulas used in this numerical problem

Numerical problem – a ball thrown vertically upwards
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