In this post, we will *derive the equations for the Excess pressure inside Liquid Drop and Liquid Bubble*.

Small-sized liquid drops and a bubble are spherical in shape due to surface tension.

The liquid surface is curved; therefore there is an excess pressure; p; inside the liquid drop or a bubble.

**Liquid Drop** – Excess pressure equation derivation

Consider a liquid drop of radius r, surface tension S as shown in Fig. Let p be the excess pressure inside liquid drop.

Very slowly we increase the radius of the drop to (r + dr). Work has to be done due to force because of excess pressure. Consider a small area dA on the surface of the drop.

Force on the area considered due to excess pressure = p.dA.

Work done against surface tension to increase the radius of drop by dr = (p.dA).dr.

**The total work done, dW = Σ(p.dA).dr = p [ΣdA].dr = p.[4πr ^{2}] dr ……… (1)**

[ ΣdA = Total surface area of liquid drop = 4πr^{2} ^{ }]

The work done appears as an increase in the free energy dE of a liquid drop.

**Obviously, dE = Increase in surface area × S = 4π [(r+dr) ^{2} – r^{2}]x S = 8πrS.dr…..(2)**

From law of conservation of energy, dW = dE

p.[4πr^{2}] dr = 8πrS.dr

or p = 2S/ r …..(3)

**Liquid Bubble** – Excess pressure equation derivation

A liquid bubble has two free surfaces. Therefore excess pressure p = 4S/r ……… (4)