PhysicsTeacher.in

High School Physics + more

A 52 N sled is pulled across a cement sidewalk at a constant speed. A horizontal force of 36 N is exerted. What is the coefficient of sliding friction between the sidewalk and the metal runners of the sled? [Friction Numerical]

Numerical Question: A 52 N sled is pulled across a cement sidewalk at a constant speed. A horizontal force of 36 N is exerted. What is the coefficient of sliding friction between the sidewalk and the metal runners of the sled?

Solution:

Weight of the sled = 52 N. Here the normal force on the Slade = FN (sled) = 52 N
Hence the friction working against its motion = FF= μFN = μ 52 = 52μ (here μ is the coefficient of sliding friction between the sidewalk and the metal runners of the sled)

As the sled is moving at a constant speed that means the net force on it is zero. This implies that the horizontal force of 36 N on it just equals the friction in magnitude.
Hence, 52μ = 36
=> μ = 36/52 = 0.69

Answer: The coefficient of sliding friction between the sidewalk and the metal runners of the sled is 0.69

See also  How do Running shoes increase the force of static friction exerted by the ground on the athlete?
Scroll to top
error: physicsTeacher.in