To calculate the **acceleration due to gravity near the surface of the moon** we will use the formula **g = GM_{moon} / R_{moon}^{2}**

Here G = universal gravitational constant = 6.67 × 10

^{−11}N · m

^{2}/kg

^{2}

M

_{moon}= 7.35 × 10

^{22}kg

and

R

_{moon}= 1.738 × 10

^{6}m

**g**= (6.67 × 10

_{moon}= GM_{moon}/ R_{moon}^{2}^{−11})(7.35 × 10

^{22})/(1.738 × 10

^{6})

^{2}m/s

^{2}

=>

**g**= 1.62 m/s

_{moon}^{2}

## What is the value of acceleration due to gravity near the surface of the moon?

The value of acceleration due to gravity near the surface of the moon = **g _{moon}**= 1.62 m/s

^{2}

## Solve a numerical problem – Using g value near the moon surface

**What would be the weight of a 10 kg mass on the surface of the moon? What be the value if the same mass is brought to the earth?**

**Solution:**A 10-kg mass would weigh only 16.2 N

*on the moon*since F

_{g}= m

**g**= (10 kg)(1.62 m/s^2) =

_{moon}**16.2 N**

And It would weigh (10 kg)(9.8 m/s^2) =

**98 N on earth**