A block of mass 1 kg slides down on an inclined plane of inclination 60 degrees. Find the work done by the block’s weight as it slides through 100 cm.
mass = 1kg.
Weight = 1x 9.8 N = 9.8 N
So the force to be considered is the weight = F=9.8 N in the downward direction.
And as the displacement is along the inclined plane, from the diagram it’s clear that the angle between the force and displacement is = (180-90-60) = 30 degrees.
Displacement = 100 cm = 1 m
So the work done is W = FS Cos θ = 9.8 x 1x Cos 30 = 8.487 J